June 02, 2020, 11:49:17 AM
Forum Rules: Read This Before Posting


Topic: Quantum Numbers & Electron Configuration  (Read 2408 times)

0 Members and 1 Guest are viewing this topic.

Offline SchoolBoyDJ

  • New Member
  • **
  • Posts: 3
  • Mole Snacks: +0/-0
Quantum Numbers & Electron Configuration
« on: April 24, 2008, 08:49:16 PM »
I'm having some trouble understanding a type of question about electrons in an element.  I'm simply reviewing topics from last semester because out final this semester is a cumulative of last semester and this semester (who signed me up for this?).  I understand a question such as the following: What is the maximum # of electrons that can have the following sets of quantum #s?  And then she'll name of n=2 , l= 1 etc etc...I understand those.  The question I'm getting confused on is:

1.  How many total electrons does Bi contain having n=4?

2.  How many total e- does P contrail having n=3, l=1?

And there are many more of the same type.

For question 1 all I thought I'd have to do is 2n^2, 32 e-, which is correct.

#2 ml= -1, 0, 1...3 possibilities of ml, 2 posibilies of ms each makes 6 electrons...However the answer is 3...


Can someone explain this to me please  ???

Thanks!

Offline enahs

  • 16-92-15-68 32-7-53-92-16
  • Retired Staff
  • Sr. Member
  • *
  • Posts: 2179
  • Mole Snacks: +206/-44
  • Gender: Male
Re: Quantum Numbers & Electron Configuration
« Reply #1 on: April 24, 2008, 08:58:26 PM »
For question 2, you figure out how many electrons are possible in the P-shell. Correct?
l=1 is P-shell, no?

However, look at the periodic chart. How many electrons are actually in the P-shell for Phosphorus?

Offline SchoolBoyDJ

  • New Member
  • **
  • Posts: 3
  • Mole Snacks: +0/-0
Re: Quantum Numbers & Electron Configuration
« Reply #2 on: April 24, 2008, 09:06:22 PM »
Wow.  LoL  it's the easy ones that stump ya sometimes :P  Overthinking things is easy to do in chem I guess >_>

Thanks!

Sponsored Links