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Topic: Relation between ∆Go and K  (Read 7001 times)

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Offline harini_5

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Relation between ∆Go and K
« on: April 24, 2008, 04:01:09 AM »
In the chapter of chemical equilibrium I’m learning a relation between ∆Go and equilibrium constant K which is, ∆Go = -RTlnK
But when to substitute K as Kp, Kc or Kx?


Offline Yggdrasil

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Re: Relation between ∆Go and K
« Reply #1 on: April 24, 2008, 02:45:48 PM »
This equation gives the value of Kc

Offline harini_5

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Re: Relation between ∆Go and K
« Reply #2 on: April 25, 2008, 10:41:42 AM »
This equation gives the value of Kc
But a few books like O.P.Agarwal,"IIT CHEMISTRY" says it is Kp . my text book says the usage depends upon the CONTEXT but I'm not able to get any conceptual clarity.

Offline Yggdrasil

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Re: Relation between ∆Go and K
« Reply #3 on: April 25, 2008, 09:18:48 PM »
Actually, I was mistaken.  For reactions involving ideal gasses, ∆Go = -RTlnKp.   ∆Ao = -RTlnKc, where A is the helmholtz free energy.  The explanation why requires some advanced knowledge of statistical thermodynamics, but it has do do with the special properties of the Gibbs free energy under conditions of fixed temperature and pressure, and the special properties of the Helmholtz free energy under conditions of fixed temperature and volume.

Offline harini_5

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Re: Relation between ∆Go and K
« Reply #4 on: April 26, 2008, 04:12:52 AM »
So what to conclude?Is there any hint that I could get from my question that would suggest which equilibrium constant to be used?

Offline Yggdrasil

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Re: Relation between ∆Go and K
« Reply #5 on: April 26, 2008, 12:02:56 PM »
It depends on what kind of reaction you are looking at.  For a reaction involving ideal gasses, ∆Go = -RTlnKp.  For a reaction involving solutes in an ideal solution, ∆Go = -RTlnKc.

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