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Charle's Law Problem

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rvf263:
Hi all,
I feel stupid asking for help with such easy problems, but I'm just learning so I have to do what I have to do...lol
I've done this problem a couple times and still can't get the correct answer. I thought I was setting them up right to solve, but apparently not.
Anyway, I would appreciate any help to show where I'm going wrong.

"A gas sample is cooled from 100. oC. The gas sample volume was reduced from 2.00 L to 1.20 L. To what temperature in Celsius was the sample of gas cooled?"

I set it up to solve for T2 = V1/V2 x T1

T2 = 2.00L / 1.20L x 373

I think I'm close, but I can't see what I'm doing wrong.


Thanks,
Robert

Mitch:
Maybe the gas wouldn't of been cooled if you compress it. ;)

rvf263:
:)

So is the problem set up correctly?

pkothari13:
Well, you know the law is V1/T1 = V2/T2

Say 2.0 L  = V1, 373 = T1, 1.20 L = V2 and T2 = (x+273).

Therefore,

2/373 = 1.2/(x+273)
x + 273 = (1.2)(373)/2
x = (1.2)(373)/2 - 273
x = -49.2 o C

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