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Topic: Equation of state  (Read 10803 times)

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Offline vdemas

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Equation of state
« on: June 24, 2008, 06:05:05 AM »
Q : Use [dU/dV]T = T [dp/dT]V - p to derive the equation mu = [T(dV/dT)p - V] / Cp.


All I have thus far is :

T = [dU/dS]V and  -p = [dU/dV]S

Offline Hunt

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Re: Equation of state
« Reply #1 on: July 17, 2008, 12:47:20 PM »
What does "mu" represent ?

Offline Hunt

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Re: Equation of state
« Reply #2 on: July 18, 2008, 01:27:22 PM »
I suppose "mu" is the Joule-Thomson coefficient.

The key is to express the differential of H as a function of "mu" .

dH = (dH / dP) dP + (dH / dT) dT

Euler's chain rule : (dH / dP)(dP / dT )( dT / dH ) = -1

mu = - (dH / dT)(dP / dH)


dH = - u Cp dP + Cp dT

This is a standard result.

H= U + PV

Then , dH = dU + PdV + VdP

- u Cp dP + Cp dT = dU + PdV + VdP

Divide by dV keeping T constant :

- u Cp (dP/dV)T = (dU/dV)T + P + V(dP/dV)T

Substitute from the given the value of (dU/dV)T to get :

- mu Cp (dP/dV)T = T (dP/dT)V + V (dP/dV)T


mu = - 1 / Cp [ T (dP/dT)V (dV/dP)T + V ]

Using euler's chain rule for P,V, and T :

(dP/dT)V  (dV/dP)T = - (dV / dT)P


mu = 1 / Cp [ T (dV/dT)P - V ]

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