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Topic: Mg reaction with ethanoic acid...  (Read 3635 times)

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Offline Zoheb Imran

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Mg reaction with ethanoic acid...
« on: May 28, 2008, 10:43:40 AM »
My Teacher told me that if we react any group 1 metals with Ethanoic acid, then it's "OH" will be replaced by metal. E.g

Na + 2CH3CO2H------> CH3CO2Na + H2

But he said that if we react any metals from group 2 then reaction will happen like this...


1, Mg(s) + 2CH3CO2H(aq) ----> Mg(CH3CO2)2(aq) + H2(g)

however, i asked him whether this was right:

2,Mg(s) + 2CH3CO2H(aq) ----> (CH3CO2)2Mg(aq) + H2(g)
He said that this is absolutely wrong! But in my 2 Chemistry course books also from Chemistry websites i saw this, the above reaction is shown. So my question is: which one is correct way to write this reaction, 1 or 2?

Offline Borek

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Re: Mg reaction with ethanoic acid...
« Reply #1 on: May 28, 2008, 10:47:11 AM »
Do you really think you will get different answer here? ;)
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Offline Zoheb Imran

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Re: Mg reaction with ethanoic acid...
« Reply #2 on: May 28, 2008, 10:50:46 AM »
u again!! lol   :o

dude i am just getting different opinion and answers from different people!!  :P


but u showed up!! what a surprise !!

Offline Astrokel

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Re: Mg reaction with ethanoic acid...
« Reply #3 on: May 28, 2008, 11:21:49 AM »
Sodium ethanoate is sometimes written as CH3COO-Na+ or simply CH3COONa, because the negative charge is spread over the carboxylate system. Same thing applicable to Mg.
No matters what results are waiting for us, it's nothing but the DESTINY!!!!!!!!!!!!

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