4-Isopropylbenzoic acid is what I would say too.
The 6H, d and 1H, sept screams isopropyl group. 1705 in the IR is typical for a carboxylic acid.
You have 4 aromatic protons, and in order to get the two doublets you would need para substitution in the ring.
The problem with isopropyl benzoate is a) 1705 is really too low to be an ester and b) inconsistent with the aromatic region of the nmr