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### Topic: hi, another question  (Read 25746 times)

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#### klumba

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##### Re: hi, another question
« Reply #15 on: November 19, 2009, 08:52:18 PM »
7?

#### Borek

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##### Re: hi, another question
« Reply #16 on: November 20, 2009, 02:55:41 AM »
Is 45 divisible by 7?

Be warned: I am not going to play the game in which you will list all possible integer numbers asking if they are correct. You have one last try, finding gcd is not a rocket science.
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#### klumba

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##### Re: hi, another question
« Reply #17 on: November 20, 2009, 05:44:30 PM »
no,no...i meant 15...  i divided 105 by 15 and got 7...so typed the wrong number..
but still...don't these numbers should be divided by the smallest number among them and not by gcd?

#### Borek

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##### Re: hi, another question
« Reply #18 on: November 20, 2009, 07:24:08 PM »
no,no...i meant 15...  i divided 105 by 15 and got 7...so typed the wrong number..

OK, so now you have muyour multiple proportions.

Quote
but still...don't these numbers should be divided by the smallest number among them and not by gcd?

No. They have to be converted into set of lowest integer numbers that have the same ratios that the original ones. 0.75/0.45 doesn't yield an integer, 0.75/0.15 does.
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#### klumba

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##### Re: hi, another question
« Reply #19 on: November 20, 2009, 08:09:25 PM »
so, there is no direct relationship between obtained massed? I have to explain it " because all of them a multiple to 0.15 and give whole numbers, it supports the law of multiple proportions"? I am sorry, but I reeeeeeeeeeally don't get it

#### Borek

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##### Re: hi, another question
« Reply #20 on: November 21, 2009, 04:26:03 AM »
It doesn't matter multiples of what they are. It is their ratios that count and ratio of 1.05:0.75:0.45 is identical to 7:5:3 - three small integers. And fact that these are small integers is exactly what law of multiple proportions says.
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#### klumba

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##### Re: hi, another question
« Reply #21 on: November 21, 2009, 10:57:35 AM »
ooooooooooooh, i got it now! thank you!!!