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Topic: pH of several solutions  (Read 9779 times)

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Offline Wheeler004

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pH of several solutions
« on: June 04, 2008, 05:40:24 PM »
I need some help getting the pH of some solutions:

-pH of a solution of 10.0 mL of 0.1 M NH4Cl plus 10.0 mL of 0.1 M NaOH
-pH of a solution of 10.0 mL of 0.1 M NH4Cl plus 15.0 mL of 0.1 M NaOH
-pH of a solution of 10.0 mL of 0.1 M NaC2H3O2 plus 10.0 mL of 0.1 M NaOH
-pH of a solution of 10.0 mL of 0.1 M NaC2H3O2 plus 15.0 mL of 0.1 M NaOH
-pH of 50 mL of solution that is 0.25 M in both H2PO41- and HPO42-.

For the life of me I can't figure out how to do these problems, so if someone could show me how I would appreciate it.  Thanks.
« Last Edit: June 04, 2008, 06:05:00 PM by Wheeler004 »

Offline Borek

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Re: pH of several solutions
« Reply #1 on: June 04, 2008, 06:11:09 PM »
Write reaction equation whenever it looks like the reaction is possible. In most cases pH will be controlled by the excess of one reagent.

As for the last one - do you know Henderson-Hasselbalch equation?
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Offline Wheeler004

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Re: pH of several solutions
« Reply #2 on: June 04, 2008, 06:25:56 PM »
OK, thanks for the website.  After doing the equation for the last solution, I got 5.05.  It looks right to me, but it's being counted as wrong when I submit it.

Offline AWK

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Re: pH of several solutions
« Reply #3 on: June 05, 2008, 12:58:57 AM »
For the last solution pH=pK2of H3PO4= 7.2
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Offline Borek

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Re: pH of several solutions
« Reply #4 on: June 05, 2008, 02:49:20 AM »
After doing the equation for the last solution, I got 5.05.

Show how you get to 5.05.
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Offline Wheeler004

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Re: pH of several solutions
« Reply #5 on: June 05, 2008, 04:52:35 PM »
Okay, I got the last one using the H-H formula.  The first time I was just using pKa.  Any help on the first four?  How do I calculate the H3O+ concentration for those?

Offline Borek

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Re: pH of several solutions
« Reply #6 on: June 05, 2008, 06:13:17 PM »
I hate to repeat myself.

Write reaction equation whenever it looks like the reaction is possible. In most cases pH will be controlled by the excess of one reagent.
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Offline Wheeler004

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Re: pH of several solutions
« Reply #7 on: June 05, 2008, 08:21:14 PM »
Yeah, I've tried that.  For the first one, there are 10ml of .1M acid and 10mL of .1M base.  Doesn't that mean that there is no excess of either?  I tried a pH of 7, but that's not the right answer.

Offline Borek

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Re: pH of several solutions
« Reply #8 on: June 06, 2008, 03:00:11 AM »
Yeah, I've tried that.  For the first one, there are 10ml of .1M acid and 10mL of .1M base.  Doesn't that mean that there is no excess of either?  I tried a pH of 7, but that's not the right answer.

But you are close - just think it over. You started with witch a weak acid and you neutralized it with a stoichiometric amount of the strong base. What ions/molecules do you have in solution after that? Is there any that can change pH of the solution?
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