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Topic: Writing a ReDox Reaction  (Read 3434 times)

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Offline Herst

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Writing a ReDox Reaction
« on: June 16, 2008, 09:32:12 PM »
"The reaction between aqueous solutions of Cu(NO3)2 and KI  form CuI and I2. The CuI precipitates from the reaction as a solid, and the other products (KNO3 and I2) remain in aqueous solution.

Write a balanced molecular equation for the overall reaction, using the smallest whole number coefficients, including the states of matter for each reactant and product."

The only answer I can think of is

Cu(aq) + I(aq) -> CuI(aq)  , which I found by removing the spectator ions and keeping the molecules         which are necessary for precipitation.

Can someone help me understand how to do this please?

Offline AWK

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Re: Writing a ReDox Reaction
« Reply #1 on: June 17, 2008, 01:09:19 AM »
Balance it
Cu(NO3)2(aq) + KI(aq) = CuI(s) + KNO3(aq) + I2(s)
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Offline Borek

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Re: Writing a ReDox Reaction
« Reply #2 on: June 17, 2008, 03:14:06 AM »
The only answer I can think of is

Cu(aq) + I(aq) -> CuI(aq)

First of all - I2 should be a product, it is not in your reaction equation.

Second - you have omitted charges, you can't. Your must balance both atoms and charge.
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