March 29, 2024, 09:40:49 AM
Forum Rules: Read This Before Posting


Topic: Rate of Reactions  (Read 3684 times)

0 Members and 1 Guest are viewing this topic.

Offline chaneliman

  • Regular Member
  • ***
  • Posts: 18
  • Mole Snacks: +1/-9
Rate of Reactions
« on: June 20, 2008, 07:58:45 AM »
Can you just clear some things up for me;

Natural gas begins to burn when lit with a match. Why does it continue to burn when the match is taken away? (i think it has something to do with activation energy?)

Why must the energy absorbed, when the bonds break, be less than the energy released when new bonds form in the combustion of methane; which results in an overall release of thermal energy?

Why does a small increase in temperature have a greater impact on the rate than an increase at higher temperatures?

Offline Astrokel

  • Full Member
  • ****
  • Posts: 989
  • Mole Snacks: +65/-10
  • Gender: Male
Re: Rate of Reactions
« Reply #1 on: June 20, 2008, 12:26:49 PM »
1. Yes the lit provides an external energy for the reaction to reach its activation energy, however, there must be another source of energy to keep it from burning.(hint: look at the main composition of natural gas and part 2)

2. That is because products of combustion of methane(CO2 &H2O) are more energetically stable than the reactants. So in a sense, reactants are relatively less stable, so the bonds are easier to be break, therefore energy absorbed is lesser. Whereas, products are relatively more stable, so their bonds are easier to formed, therefore more energy is released. Hence, overall is always an exothermic process.

3. This is probably due to the nature of exponetial graph. Do you know about Arrhenius' equation?
No matters what results are waiting for us, it's nothing but the DESTINY!!!!!!!!!!!!

Sponsored Links