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Topic: Gibbs free energy  (Read 8929 times)

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Offline vdemas

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Gibbs free energy
« on: June 25, 2008, 10:35:55 AM »
Please check if I did this correctly.

Q : The change in Gibbs energy of a certain constant-pressure process
      was found to fit the expression

              deltaG/J = -73,1 + 42,8 (T/K)

A :  deltaG = deltaH - T deltaS
                 = -73,1 + 42,8 T

   Express this equation to solve for delta S:

      deltaG = deltaH - T deltaS
      -T deltaS = deltaG - deltaH
      T deltaS = deltaH - deltaG
       deltaS = (deltaH - deltaG) / T
                  = [(-73,1) - (-73,1 + 42,8T)] / T
                  = (-73,1 + 73,1 - 42,8T) / T
                  = - 42,8T/T
                  = - 42,8 J/K

Offline Hunt

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Re: Gibbs free energy
« Reply #1 on: July 17, 2008, 12:48:42 PM »
correct

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