I'd appreciate if someone could post a solution to this
Balance the following equations
Ce(SO4)2 + NaNO2 + H20 - Ce2(SO4)3 + NaNO3 + H2SO4
(NH4)2SO4FeSO4 + Ce(SO4)2 - Fe2(SO4)3 + Ce2(SO4)3 + (NH4)2SO4
In a laboratory experiment to calculate the % of nitrite ion NO2 in a salt 1.639 g of sodium nitrogen (IV) oxide, NaNO2 were made up to 500cm3 with deionised water. 25cm3 of this solution were added to 50cm3 of cerium (IV) sulphate
Ce(SO4)2.4H20 and 10cm3 of 2M sulphuric acid in a conical flask. The concentration of the cerium (IV) sulphate was 39.093 gdm-3. After 5 minutes the excess cerium (IV) sulphate was titrated with a standard solution of ammonium iron (II) sulphate hexahydrate, (NH4)2SO4FeSO4.6H20. If this required 23.7cm3 of iron salt and if the concentration of the iron salt was 41.196gdm-3 calculate the % of nitrite ion in the sodium nitrogen (IV) oxide salt.