[slu1986]

Write a balanced net ionic equation for the reaction below:

       Pb(NO3)2 (aq) + NaI (aq) ----->

A) Pb(NO3)2 (aq) + 2NaI (aq) ---> PbI2 (s) + 2NaNO3 (aq)
B) Pb^2+ (aq) + 2NO3- (aq) + 2Na^+ (aq) + 2I- (aq) --> Pb^2+ (aq) + 2I- (aq) + 2Na^+ (aq) + 2NO3- (aq)
C) Pb^2+ (aq) + 2NO3- (aq) + 2Na^+ (aq) + 2I- (aq) ---> PbI2 (s) + 2Na^+ (aq) + 2NO3- (aq)
D) Pb^2+ (aq) + 2I- (aq) ---> PbI2 (s)   <-----this is the answer that I got

This is how I solved the problem:

Pb(NO3)2 (aq) + 2NaI (aq) ----> PbI2 (s) + 2NaNO3 (aq)
Pb^2+ (aq) + 2NO3- (aq) + 2Na+ (aq) + 2I- (aq) ---> PbI2 (s) + 2Na+ (aq) + 2NO3- (aq)
Pb^2+ (aq) + 2I- (aq) ---> PbI2 (s)

Just wondering If I did this correct and got the right answer

[Borek]

Answer is OK.