April 17, 2021, 10:18:28 PM
Forum Rules: Read This Before Posting


Topic: Question regarding enthalpy of reaction/ heat of formation using bond energies  (Read 22485 times)

0 Members and 1 Guest are viewing this topic.

Offline slu1986

  • Regular Member
  • ***
  • Posts: 68
  • Mole Snacks: +0/-0
Estimate the ΔH°, in kJ for the following reaction from the bond energies given.

                          H2 (g) + I2 (g) ---> 2 HI (g)

Bond energy (kJ/mol): H-H = 436 H-I = 297 I-I = 151

A) 884
B) -290
C) +290
D) +7
E) -7 <-----this is the answer that I got

This is how I got it:

ΔH bond breakage:
1 mol H-H bonds = 436 kJ
1 mol I-I bonds = 151 kJ
Total = 436 + 151 = 587

ΔH bond formation:
2 mol H-I bonds = (2 X -297)kJ = -594 kJ

ΔH° rxn = 587 kJ + -594 kJ = -7 kJ

Use the bond energies below to estimate the heat of formation of hydrogen fluoride gas, in kJ/mol.

       H-H = 436 kJ/mol     H-F = 569 kJ/mol    F-F = 159 kJ/mol

               1/2 H2 + 1/2 F2 -----> HF

A) +298
B) +271
C) -271<------this is the answer that I got
D) -542
E) -298

This is how I got it:

ΔH bond breakage:
1/2 mol H-H bonds = (1/2 X 436) kJ = 218 kJ
1/2 mol F-F bonds = (1/2 X 159) kJ = 79.5 kJ = 80 kJ
Total = 218 + 80 = 298 kJ

ΔH bond formation:
1 mol H-F bonds = - 569 kJ

ΔH°f = 298 kJ + -569 kJ = -271 kJ

I was just wondering If someone could let me know If I solved both problems right and got the correct answers.  Thank You  :)

Offline tamim83

  • Retired Staff
  • Full Member
  • *
  • Posts: 395
  • Mole Snacks: +67/-7
  • Gender: Female
  • Quantum Kitten
Looks fine to me ;D

Sponsored Links