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Topic: Saponification Reaction Calculations  (Read 12851 times)

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Offline breathoffire

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Saponification Reaction Calculations
« on: July 30, 2008, 01:39:26 PM »
Okay I have been trying to figure out how to do these calculations for a couple of day and am still having a hard time figuring them out. In the Lab I titrated 18.3ml  0.25 M HCl with KOH in a control sample without oil then 2 with oil getting 10.3ml of 0.25 M HCl in butter and 10.6ml of 0.25 M HCl in olive oil. To calculate the moles of OH in the flask I used this equation 0.0183Liters x 0.25mol/ 1liter and got 0.00458mols in the control, 0.00258mols OH for butter and 0.0027mols OH for Olive oil. Then to calculate the mols of OH consumed in the Saponification reaction I subtracted the moles of OH calculated in the flask from the moles of OH calculated in the control flask (0.00458-0.00258)=0.00201 mols for the butter and 0.00193 mols for the olive oil. After all of this the problem I am having is calculating the mols of triacylglycerol molecules from each sample the lab manual says to use stoichiometry to determine this but I have no idea what equation to use. If anyone has any ideas I am willing to try them.





Offline Yggdrasil

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Re: Saponification Reaction Calculations
« Reply #1 on: July 30, 2008, 05:20:39 PM »
During saponification of a triacylglycerol molecule, how many OH- ions are consumed.  If you know this ratio, you can go from moles of OH- consumed to moles of triacylglycerol.

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