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Topic: pH 12 diluted with pH 8  (Read 3872 times)

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selway

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pH 12 diluted with pH 8
« on: April 01, 2005, 04:14:44 PM »
Hello, I have a complicated pH question.  I have a 8 inch pipe that discharges 20,000 gallons/day and measurements of the pipe pH are 12.  If the volume was increased to 40,000 gallons/day with water with a pH of 8, what would the final pH be?

I am so confused.  I tried calculating moles of H+, but my volume is a rate, not an actual volume, so how do I change that to mol/liter?

AND, what if I just know the pH but not the chemical that is providing it?  

Offline Borek

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Re:pH 12 diluted with pH 8
« Reply #1 on: April 01, 2005, 05:30:08 PM »
Forget about rates. Imagine you have collected all water in the poll and make your calculations on known volumes.
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Offline AWK

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Re:pH 12 diluted with pH 8
« Reply #2 on: April 04, 2005, 02:42:28 AM »
As a first aproximation, you can treat the problem, as dilution of water with pH=12  (twice). Forget about water with pH=8
« Last Edit: April 04, 2005, 05:08:56 AM by AWK »
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