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Topic: Forum Now Supports LATEX!  (Read 95452 times)

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Offline Schrödinger

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Re: Forum Now Supports LATEX!
« Reply #30 on: March 17, 2010, 02:44:29 PM »
Is it possible for me to hide my text?

Like... the heading says 'click to reveal content (or something else)' and when you click on it the hidden text appears...like in the mathlinks forum?
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Offline Mitch

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Re: Forum Now Supports LATEX!
« Reply #31 on: March 17, 2010, 02:52:26 PM »
The internet use to use Rot 13 for things like that.

Srry serr gb hfr vg urer ng purzvpnysbehzf.pbz
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3. Forum Supports LaTex

Offline Schrödinger

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Re: Forum Now Supports LATEX!
« Reply #32 on: March 18, 2010, 12:48:12 AM »
Gunax lbh, ohg vfag guvf whfg qrpbqvat ?
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Offline Mitch

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Re: Forum Now Supports LATEX!
« Reply #33 on: March 18, 2010, 12:55:37 AM »
Lrnu, ohg va n frafr vg npgf yvxr n fcbvyre gnt. Juvpu frrzf gb or jung lbh jrer trggvat ng.
</rot 13>
Most Common Suggestions I Make on the Forums.
1. Start by writing a balanced chemical equation.
2. Don't confuse thermodynamic stability with chemical reactivity.
3. Forum Supports LaTex

Offline Schrödinger

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Re: Forum Now Supports LATEX!
« Reply #34 on: March 18, 2010, 01:03:48 AM »
Ok, I'm getting tired of having to refer to Wikipedia every time to decode this. It's consuming a lot of time. What does </rot 13> do? I can't seem to use it in my posts
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Offline Mitch

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Re: Forum Now Supports LATEX!
« Reply #35 on: March 18, 2010, 02:57:04 AM »
It doesn't mean anything, I just put it so you would know what I was doing.

More importantly, you have been doing this by hand!?? Just use this: http://www.rot13.com/
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2. Don't confuse thermodynamic stability with chemical reactivity.
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Offline Schrödinger

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Re: Forum Now Supports LATEX!
« Reply #36 on: March 18, 2010, 08:08:33 AM »
Thanks for the link Mitch. I'm starting to like this now.
Oh... and please don't mistake my tone in my last post... I was getting totally stressed out doing it by hand
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Offline Matias Ekstrand

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Re: Forum Now Supports LATEX!
« Reply #37 on: April 01, 2010, 12:20:21 PM »
I'm not exactly sure how you integrated LaTeX into the forum. You didn't use the Mimetex SMF-mod for it due to the different tags and lack of latex button in the text editor menu, so I suppose you made something custom.

I tend to use LaTeX a lot, and the use of a button in the text editor menu to get the tags makes it much simpler to integrate into forum posts.

My suggestion:
- It might be easier for you to use the Mimetex SMF-mod (doesn't cause problems at forum updates compared to custom code).
- If not, could you please create a BBCode button for the LaTeX tags? You could probably use this mod for creating it.
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Offline haz658

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Re: Forum Now Supports LATEX!
« Reply #38 on: April 21, 2010, 04:45:33 PM »
Practicing.


Code: [Select]
$$ y = mx +b /$$

Offline haz658

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Re: Forum Now Supports LATEX!
« Reply #39 on: April 21, 2010, 04:46:11 PM »
Practicing.

$$ y = mx + b /$$

Offline haz658

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Re: Forum Now Supports LATEX!
« Reply #40 on: April 21, 2010, 10:19:43 PM »
Determining whether what I am about to post will turn out properly. My apologies.



$$\begin {eqnarray} ln \left (\frac{W_{max}} {W} \right) & = & \sum_{n} a_n \alpha_n \mathbf {ln a_n} + \sum_{n} \frac {a_n} {2} (\alpha^{2}_{n})  \nonumber  \\  & = & \sum_{n} a_n \alpha_n \mathbf {(ln a_0 - \beta \varepsilon_n)} + \sum_{n} \frac {a_n} {2} (\alpha^{2}_{n})  \nonumber \end{eqnarray} /$$

Offline haz658

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Re: Forum Now Supports LATEX!
« Reply #41 on: April 21, 2010, 10:24:27 PM »

$$\begin {equarray*} ln \left (\frac{W_{max}} {W} \right) & = & \sum_{n} a_n \alpha_n \mathbf {ln a_n} + \sum_{n} \frac {a_n} {2} (\alpha^{2}_{n}) \\ & = & \sum_{n} a_n \alpha_n \mathbf {(ln a_0 - \beta \varepsilon_n)} + \sum_{n} \frac {a_n} {2} (\alpha^{2}_{n}) \end{equarray*} /$$

Offline haz658

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Re: Forum Now Supports LATEX!
« Reply #42 on: April 21, 2010, 10:26:11 PM »

$$\begin {eqnarray*} ln \left (\frac{W_{max}} {W} \right) & = & \sum_{n} a_n \alpha_n \mathbf {ln a_n} + \sum_{n} \frac {a_n} {2} (\alpha^{2}_{n}) \\ & = & \sum_{n} a_n \alpha_n \mathbf {(ln a_0 - \beta \varepsilon_n)} + \sum_{n} \frac {a_n} {2} (\alpha^{2}_{n}) \end{eqnarray*} /$$



$$\begin {eqnarray} ln \left (\frac{W_{max}} {W} \right) & = & \sum_{n} a_n \alpha_n \mathbf {ln a_n} + \sum_{n} \frac {a_n} {2} (\alpha^{2}_{n}) \\ & = & \sum_{n} a_n \alpha_n \mathbf {(ln a_0 - \beta \varepsilon_n)} + \sum_{n} \frac {a_n} {2} (\alpha^{2}_{n}) \end{eqnarray} /$$

Offline haz658

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Re: Forum Now Supports LATEX!
« Reply #43 on: April 21, 2010, 10:46:46 PM »
My first question is how the authors were able to convert $ ln a_n /$ to $ (ln a_0 - \beta \varepsilon_n /$ , where an is the occupation number of the nth energy level,

Offline haz658

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Re: Forum Now Supports LATEX!
« Reply #44 on: April 24, 2010, 01:44:21 PM »
Sorry. Still practicing.

$$ \frac {dlnW} {da_n} = 0 /$$ for the Boltzmann distribution

$$ a_n = Ne^{\alpha} e^{- \beta \varepsilon_n} /$$

$$ ln a_n = ln a_0 - \beta \varepsilon_n /$$

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