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Topic: Empirical Formula  (Read 4013 times)

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Offline qbkr21

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Empirical Formula
« on: September 09, 2008, 08:56:39 PM »
I need some help finding the Empirical Formula  ???

(I) 0.0091 mol C, 0.0186 mol H, and 0.0045 mol O

0.0001 Mol C/0.0045 = 2.02222222222222222222222222222222222222
0.0186 Mol H/0.0045 = 4.13333333333333333333333333333333333333
0.0045 Mol O/0.0045 = 1

I know I need to multiply to get closer to a whole number, but by what.

Thanks,

qbkr21

Offline dabaichi

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Re: Empirical Formula
« Reply #1 on: September 10, 2008, 12:13:54 AM »
I'd say the ratio is close enough. There is really no way to make it more of a whole number. C2H4O is a very possible answer.
« Last Edit: September 10, 2008, 12:28:37 AM by dabaichi »

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