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Topic: Equivalence Mass  (Read 6351 times)

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Offline Sturm88

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Equivalence Mass
« on: September 13, 2008, 11:14:17 PM »
Phosphorous in a Fertilizer

"P205" (cited by manufacturer) --> (NH4)H2PO4 (actual fertilizer) --> MgNH4PO4.6H2O (product)

So P2O5 apparently isn't the actual phosphorous in fertilizer it's ammonium dihydrogen phosphate.

If I have 1 gram of the fertilizer (MgNH4PO4.6H20) initially what's the equivalence mass of the imaginary "P2O5"

I've thought about it and I'm a little confused. Not sure what to use.

Since there are two hydrogens in the actual fertilizer and 2P's in the phosporic acid... I have tried this.

MolarMass of P2O5 / 2 for equivalence mass... but I'm not sure if that's what is needed to be done.


Offline Borek

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Re: Equivalence Mass
« Reply #1 on: September 14, 2008, 05:32:37 AM »
Try to write reaction of fertilizer "synthesis" that starts with P2O5. Something like CaO + P2O5, where there is obviously 141.9 g of P2O5 in 321.2 g of Ca3(PO4)2.
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