[Guitarmaniac86]

I am not feeling myself at the moment. I cant think and I need someone to verify my calculations.

I made up a 5ppm solution of Copper(II)sulphate solution in a 50cm volumetric flask.

5 ppm = 5mg/L

Therefore there are 5mg of Cu(II) ions per litre giving.

Moles = 5x10^-3 / 63.55 = 7.87x10^-5 moles.

Concentration = Moles x1000 / V

Therefore:

C = 7.87x10^-5 x 1000 / 50

C = 1.57 x 10^-3 mol dm^3

Is this correct?

[Borek]

Therefore there are 5mg of Cu(II) ions per litre giving.

Moles = 5x10^-3 / 63.55 = 7.87x10^-5 moles.

That's number of moles in a liter of the solution. That's what I already call concentration

[Guitarmaniac86]

Therefore there are 5mg of Cu(II) ions per litre giving.

Moles = 5x10^-3 / 63.55 = 7.87x10^-5 moles.

That's number of moles in a liter of the solution. That's what I already call concentration

I feel like such an idiot.

I totally missed this: 5 ppm = 5mg/L

Divide 5mg/L by copper RAM I get mol/L which is Mol dm^-3

I am retarded...

(I didnt look at the units -.- and assumed I was wrong)