in my A level syllabus we learnt about Chlorine reacting with cold and hot NaOH to hypochlorite and chlorate respectively, it is a disproportion reaction, so i can't tell is it because of chlorine strong oxidizing ability or weak reducing ability(relative to bromine and iodine) doing its effects. So i am wondering if other halogens including florine undergo this disproportion reaction with cold/hot NaOH, if no why?
i appreciate any helps, thank you!
Coincidently, I have been editing the wikipedia pages on the chlorate (Hypochlorite, chlorite, chlorate, perchlorate) because they seemed a bit sketchy, inconsistent in style and poorly interlinked to me. I'm not claiming what is there is the final word but it makes more sense to me. If any feels they can improve, then wiki is wide open to edits.
I have started on hyopbromite and bromates. I will then move on to iodates.
The source I am using is Facts, Patterns and principles (Kneen Rogers and Simpson) which is a mega book, has loads of info and is woeful in the organisation of the material. Leaving that aside, from what I remember hypobromite (ox state +1) disproportionates directly to bromate (ox state +5). There is no (stable) bromite (ox state +3). I think the book stays there was evidence in the 1970's that the perbromates might exist fleetingly. I haven't got on to the iodate entries but I think again there are only the +1 and +5 oxidation states.
I need to check but I don't think there are any fluorooxide becasue fluroine is the strongest oxidizing agent.
Something I did find out about the disproprtionation of chlorate(I) and bromate(I) when in an alkali solution, is the second reaction rate is very temperature sensitive.