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Topic: Equilibrium pressure.. Where am I going wrong?  (Read 11221 times)

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Offline tabularasa

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Equilibrium pressure.. Where am I going wrong?
« on: October 01, 2008, 08:50:13 PM »
Consider the following reaction, equilibrium concentrations, and equilibrium constant oat a particular temperature. Determine the equilibrium pressure of CO.

CO(g) + 2 H2(g) <---> CH3OH(l)           Kp = 2.25 x 10^4
                                                      P(H2)eq= 0.52 atm

This is my work:

2.25 x 10^4 = (CO) * (.52)^2

(CO) = 8.3 X 10^4

For some reason, the answer on my practice quiz is 1.6 x10^4 atm. I know that liquids aren't present in the equation, but I don't understand why my answer is wrong.



Offline enahs

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Re: Equilibrium pressure.. Where am I going wrong?
« Reply #1 on: October 01, 2008, 08:53:44 PM »
Write out the formula for the equilibrium.
Where are you putting the CO and H2?

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