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Topic: Neutralizaton of KOH  (Read 2281 times)

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Offline ares_009

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Neutralizaton of KOH
« on: October 09, 2008, 05:28:02 PM »
I was wondering if someone could help me with this,

Q: What volume of 0.430mol/L H2S04 (aq) is required to completely neutralize 19.9mL of 1.11 mol/L KOH(aq)? answer in mL

I honestly don't know where to start, so help with where to start out would be greatly appreciated :)
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Offline Borek

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Re: Neutralizaton of KOH
« Reply #1 on: October 09, 2008, 06:12:47 PM »
Quote from: ares_009 on October 09, 2008, 05:28:02 PM
I honestly don't know where to start

Write balanced reaction equation.
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