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Offline JonyP

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Question - solutions
« on: October 10, 2008, 11:24:01 AM »
Hey guys

i have a small question if someone could help me out i'll appreciate it =)

What mass (in grams) of a 0.500m solution of sodium acetate ch3co2na, in water would you use to obtain 0.150 mol of sodium acetate?

thanks!

Offline JGK

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Re: Question - solutions
« Reply #1 on: October 10, 2008, 11:26:56 AM »
Hint: what are the units Moles as measured in?
Experience is something you don't get until just after you need it.

Offline JonyP

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Re: Question - solutions
« Reply #2 on: October 10, 2008, 11:29:21 AM »
you mean?
mass/molecular mass
?

Offline JGK

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Re: Question - solutions
« Reply #3 on: October 10, 2008, 11:38:45 AM »
No if you had a 1M solution what other units of concentration cuould it be expressed in?
Experience is something you don't get until just after you need it.

Offline JonyP

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Re: Question - solutions
« Reply #4 on: October 10, 2008, 11:39:48 AM »
molarity, molality?

Offline JonyP

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Re: Question - solutions
« Reply #5 on: October 10, 2008, 11:50:27 AM »
i've tried to use molality

0.500 = 0.150/x

then x = 0.150/0.500

x=3.0

but the answer in the book is 320g \-:

Offline Borek

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Re: Question - solutions
« Reply #6 on: October 10, 2008, 12:12:51 PM »
What mass (in grams) of a 0.500m solution of sodium acetate ch3co2na, in water would you use to obtain 0.150 mol of sodium acetate?

How many moles of sodium acetate in this solution?
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline JonyP

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Re: Question - solutions
« Reply #7 on: October 10, 2008, 12:18:32 PM »
0.500m?

Offline Borek

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Re: Question - solutions
« Reply #8 on: October 10, 2008, 01:35:50 PM »
Sorry, brain slip. Wrong question.

How many moles of acetate in 1 L of solution?

What volume of this solution contains 0.150 mole of acetate?
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline JonyP

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Re: Question - solutions
« Reply #9 on: October 10, 2008, 06:18:27 PM »
sorry man i lost u =)

do you know how to solve this?

can anyone please solve this? =)

thanks

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