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Topic: soluubility and complex ion equilibria  (Read 2388 times)

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Offline WHITECHIC9

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soluubility and complex ion equilibria
« on: October 14, 2008, 08:46:15 PM »
I wanted to see if my answer was right if you will tell me the question is what is the solubility of silver oxide in a solution buffered at pH 10.50? Kc= 2.0 X 10^-8.

Ag2O + H2O--> 2Ag+ + 2OH-


I did: pOH= 14- 10.50= 3.5
{OH-}= 10^ -3.5= 3.2 x 10 ^-4
Ksp= x^2 (3.2x10^-4)^2= 1.02x10^-7
then i square rooted them to get x= 3.2x10^-4
then I took that and multiplied by molar mass of Ag2O/mol= 7.41 x10^-2 g/L

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