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Topic: solvent extraction  (Read 6399 times)

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Offline snowie1010

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solvent extraction
« on: October 24, 2008, 05:09:43 AM »
can some1 plz help me with these. i have an assignment due and im not sure how to do these 2 Q's

1) If 176 grams of sugar are dissolved in 5.00 L of petrol, how much sugar remains in the petrol (3 sig. fig.) following a single extraction with 3.00 L of water if the partition coefficient is 2.00.

i used k=S2/S1  i got a value of 52.8g of sugar?? need to know if this is right or where i might have gone wrong

2)Methyl hydroperoxide is dissolved in 388 mL of water. How many 66 mL extractions with ether are required to remove more than 82% of the peroxide from the water is the partition coefficient is 2. (Methyl hydroperoxide is more soluble in dimethyl ether than water)

using qn=(v1/v1+kv2)n i got a value of n=0.67 which i really don't think should be right?? not sure where i would have gone wrong.

this is my first post, any help would be great, thanks

Offline JGK

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Re: solvent extraction
« Reply #1 on: October 24, 2008, 07:59:54 AM »
Please post your calculations in full, it will be easier for us to spot where you went awry
Experience is something you don't get until just after you need it.

Offline snowie1010

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Re: solvent extraction
« Reply #2 on: October 24, 2008, 08:35:16 AM »
im trying to teach my self here, but for the 1st 1 i just did

176/5=35.2g/L
then
2= 35.2/(x/3)
x=52.8g

for the 2nd i didn't really have much clue

0.82 = ln 0.746 * n

n = 0.67

Offline JGK

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Re: solvent extraction
« Reply #3 on: October 24, 2008, 10:01:44 AM »
For the first one you need to use q=(v1/v1+kv2). then apply q (fraction of the total patritioned) to the 176g

For the second one you need to use qn=(v1/v1+kv2)n and increase n on the right side until qn is > 0.82
Experience is something you don't get until just after you need it.

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