[johnnybananas]

So I have trouble balancing this equation:
Cr2O72-(aq) + C2H5OH(aq) → Cr3+(aq) + CO2(g). I balanced half of it using the half-reaction method and got this so far:
6e + 14H+ + Cr2O7 2- -> 2Cr 3+ +7H2O, but I have trouble doing the other half:
C2H5OH -> CO2 part. If someone can give me a hint to as where I should start on this other half, it would be really nice.

Thanks you.

[Borek]

Try

C₂H₅OH + H₂O = CO₂ + H⁺

[Sev]

Wouldn't Cr₂O₇^2- oxidize the alcohol to an aldehyde (or carboxylic acid)?   

[Borek]

Could be, but so far we are talking about balancing reaction where CO₂ is the product.