hi, I'm stuck on this problem hopefully someone can help.
question:
calculate the volume of 0.10M NaOH required to neutralize 10mL of 0.10M acetic acid(CH3COOH)
My attempt:
CH3COOH --> H+ + CH3COO
0.10M 0 0 (initial [ ])
-x x x (change in [ ])
----------------------------------------------------
0.10-x x x (equivalence)
ka = 0.000018
therefore, (x)(x)/0.10(assume x is small so I ignored it)=0.000018
x= 0.00134164 =[H+]
therefore, (0.00134164M H+)(0.01L H+)/(0.10M NaOH)=0.000134164L
that number just seems way too small to me but i don't know.
thanks to anyone who can help