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### Topic: Volume again: 2.50L balloon at 298 K contains butane gas. at constant pressure  (Read 3418 times)

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#### chandrablue

• Guest
##### Volume again: 2.50L balloon at 298 K contains butane gas. at constant pressure
« on: April 24, 2005, 10:58:03 AM »
A 2.50L balloon at 298 K contains butane gas. at constant pressure the temp of the balloon is then lowered to 280 K what will the new level of the volume then be?
« Last Edit: April 24, 2005, 04:18:32 PM by Mitch »

#### Garneck

• Guest
##### Re:Volume again
« Reply #1 on: April 24, 2005, 11:31:57 AM »
p1V1/T1 = p2V2/T2

p1 = p2

V1/T1 = V2/T2
2,5/298 = V2/280

V2= 2,5*280/298 = 2,35 L

#### pkothari13

• Guest
##### Re:Volume again: 2.50L balloon at 298 K contains butane gas. at constant pressur
« Reply #2 on: April 24, 2005, 04:46:29 PM »
This law is commonly known as Charles' Law. (V1/T1 = V2/T2)

At constant Temperature, it is Boyle's Law, and at constant Volume, you use Gay-Lussac's Law.

However, as Garneck demonstrated, instead of memorizing all three of these formulas, just remember the Combined Gas Law, and proceed from there.