calculate molecular weight of diprotic acid
The mass of the unknown diprotic acid = 0.326 g
Concentration of NaOH = 0.1000 M
first equivalence point vol = 6.54 ml
H2X + NaOH <---> NaHX + H2O
answer options is
Oxalic Acid H2C2O4 90
Maleic Acid H2C4H2O4 116
Malic Acid H2C4H4O5 134
Tartaric Acid H2C4H4O6 150
i know acid : base ratio is 1:2 for diprotic acid
using M V
acid == M V
baseat first equivalence point moles of acid == moles of base
at second equivalence point 2 moles of acid == moles of base
also molecular weight == grams of acid / mols of acid
im really confused with calculations , how to get the mols of acid