[student8607]

If there is 1 g in 1 mL, and 1000 mL in 1 L, then there are 1000g in a L, correct?

I see, so once you have these two interchangeable then you can just switch numbers.

1L = 1000mL & 1mL = 1.04g SO -->
1L = 1.04kg...OK

[student8607]

NO NO NO!  How many times do you need to be told something before you take it in.

I'm sorry I'm not the brightest crayon in the box.
But please don't be rude.
That is one thing I have never seen before on this forum, rudeness.

[student8607]

If there are 1.29g of Mg2+ in 1kg of sea water how many grams of Mg2+ ions are in 1L of sea water?

1.29g in 1kg
1.04kg in 1L
? g in 1L

1.34g in 1L?

1.34g x 1 mol / 24.3g = 0.055mol Mg?

[DrCMS]

NO NO NO!  How many times do you need to be told something before you take it in.

I'm sorry I'm not the brightest crayon in the box.
But please don't be rude.
That is one thing I have never seen before on this forum, rudeness.

You made the same exact error 3 times and by your third time of repeating it I got sick and tired of telling you the same thing to have you ignore what I'd said and repeat your original error again and again.

If there are 1.29g of Mg2+ in 1kg of sea water how many grams of Mg2+ ions are in 1L of sea water?

1.29g in 1kg
1.04kg in 1L
? g in 1L

1.34g in 1L?

1.34g x 1 mol / 24.3g = 0.055mol Mg?

YES!

[student8607]

OK, and then what volume measurement should I use?

[DrCMS]

OK, and then what volume measurement should I use?

For what?

[student8607]

the molarity

1L?

[DrCMS]

If there are 1.29g of Mg2+ in 1kg of sea water how many grams of Mg2+ ions are in 1L of sea water?

1.29g in 1kg
1.04kg in 1L
? g in 1L

1.34g in 1L?

1.34g x 1 mol / 24.3g = 0.055mol Mg?

Here you have calculated the number of moles of Mg in 1L of the sea water.

What is the definition of molarity?  So what is the full answer to the question?

[student8607]

molarity = moles per liter

so 0.055mol/1L = 0.055mol/L

[DrCMS]

Yes

[student8607]

WOW.
What an epic problem.
Thanks for your help.

[Borek]

What an epic problem.

Epic solution. Problem was trivial.