April 23, 2024, 09:15:33 AM
Forum Rules: Read This Before Posting


Topic: Help on drawing the correct Isomer!  (Read 2942 times)

0 Members and 1 Guest are viewing this topic.

Offline Aznhmonglor

  • Regular Member
  • ***
  • Posts: 82
  • Mole Snacks: +0/-0
Help on drawing the correct Isomer!
« on: November 15, 2008, 07:56:51 PM »
There are at least nineteen (19) isomers of molecular formula C4H8O. DRAW a bond-line structure of the isomer that is chiral, DOES contain a methyl group, is NOT an ether, but is a cyclic compound.

What I've come up with is that it has to be a cyclopropane but have no idea where the methyl group or the -OH group goes. Also chirality involves four bonds to a carbon?

Offline sjb

  • Global Moderator
  • Sr. Member
  • ***
  • Posts: 3652
  • Mole Snacks: +222/-42
  • Gender: Male
Re: Help on drawing the correct Isomer!
« Reply #1 on: November 16, 2008, 05:28:06 AM »
For the purposes of this, then yes, chirality involves four bonds to a carbon. There are more strict definitions along the lines of not being superimposable on a mirror image, but that's less important right now.

You're almost there, as you've identified that you need a cyclopropane, now where can you put a methyl group and the oxygen such that you have 4 *different* groups around a carbon?

Sponsored Links