[student8607]

This past week I did a chemistry lab that tested the freezing point of different solutes in water.

Sucrose: C12H22O11(s) + H2O(l) -->
Glucose: C6H12O6(s) + H2O(l) -->
Di-alcohol: C2H4(OH)2(aq) + H2O(l) -->
Tri-alcohol: C3H5(OH)3(aq)+ H2O(l) -->

I'm just not sure how to finish writing these "dissolution of the solid into water" equations?? Do I just group everything together like (C12H24O12) for sucrose?

I also wasn't sure if di-alcohol and tri-alcohol would classify as liquids or aqueous solutions?

[sjb]

X_(aq) means that it is already in aqueous (water) solution. X_(l) means that it is a liquid. Can you think of some other liquids that you may have come across that are not water?

You should not just group everything together like C₁₂H₂₄O₁₂ unless you are sure you are creating a new substance...

[student8607]

OK, well then the alcohols are definitely in aqueous form.

No, no new substance was formed. They were just mixed together???