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Topic: simple alkane burning  (Read 2335 times)

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Offline nejikun

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simple alkane burning
« on: November 22, 2008, 04:54:32 PM »
A mixture of gases includes hydrogen and two hydrocarbons with the same number of carbon atoms.One of the hydrocarbons is an alkane while the other is an alkene.When we fully burn 0.1 litres of this mixture it releases 0.21 litres of gas.When we use nickel as a catalisator and we heat the gases mixture they release 0.07 litres of one single gas.Find the molecular formula of each hydrocarbon and the percentage of each gas in the mixture.

From the second reaction i tried to find the volume of each element and it was 0.035 litres but that way calculating the number of carbon atoms is 0.55 and i've been trying to solve ti for too long.Please can anyone give me at least e hint?

Offline AWK

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Re: simple alkane burning
« Reply #1 on: November 24, 2008, 02:03:19 AM »
Quote
When we use nickel as a catalisator and we heat the gases mixture they release 0.07 litres of one single gas.
What volume - 0.1 L ?
You have an additional information that your mixture contains 0.3 L of hydrogen which is completely consumed by the alkene!
AWK

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