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Topic: Solubility Equilibria  (Read 4453 times)

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Superfrog

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Solubility Equilibria
« on: May 03, 2005, 12:50:06 PM »
New here, and having a tough time with the following question:

What is the solubility in g/L of silver chromate (Ksp = 1.2*10^-12), M.W=331.73 g/mol) in 0.79126M silver nitrate.  

I know the answer is 6.36 * 10^-10, but I can't get the right answer in my calculations.  

Help here would be greatly appreciated

jena

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Re:Solubility Equilibria
« Reply #1 on: May 03, 2005, 04:06:59 PM »
Hi,

I found a website to help you figure out solubility. Hope it helps. ;D

http://home.millsaps.edu/~lewisll/Ch16%20notes-2005-students.doc

Online Borek

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Re:Solubility Equilibria
« Reply #2 on: May 03, 2005, 05:42:30 PM »
Ksp = [Ag+]^2[CrO4(2-)]

[Ag+] is given as it is the same as the silver nitrate concentration. Substitute, solve for [CrO4(2-)] - you know molar concentration, you should be able to convert it to gram/L.
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GCT

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Re:Solubility Equilibria
« Reply #3 on: May 04, 2005, 09:56:39 AM »
New here, and having a tough time with the following question:

What is the solubility in g/L of silver chromate (Ksp = 1.2*10^-12), M.W=331.73 g/mol) in 0.79126M silver nitrate.  

I know the answer is 6.36 * 10^-10, but I can't get the right answer in my calculations.  

Help here would be greatly appreciated

watch out for the common ion effect

first specify whether it's silver I or silver II
e.g. silver II

Ksp=(.791+x)x

solve for x, this will be the concentration of the compound which dissolved.  You'll need to convert from moles/L, to grams/L to obtain the final answer.

The answer will be different with silver I
« Last Edit: May 04, 2005, 09:59:47 AM by GCT »

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