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Topic: Calculating Mole Fractions  (Read 13155 times)

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Offline Kingjim9

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Calculating Mole Fractions
« on: December 10, 2008, 10:00:33 PM »
Question:
Determine the mole fraction of methanol (CH3OH) IN THE VAPOR, at 25 degrees C, over a solution composed of only methanol and ethanol (C2H5OH). The mole fraction of methanol in the solution is 0.23, and the vapor pressures of pure methanol and ethanol are 155 and 62 torr, respectively, at 25 Degrees C.

My Attempt at a Solution

PA=X*PA°

so...  PMETH=(0.23)*(155) = 35.65 torr

1 MoleSolution-0.23 = 0.77 Moles of Ethanol

PETH=(0.77)*(62) = 47.74 torr


I have no idea what to do from here.

Offline Borek

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Re: Calculating Mole Fractions
« Reply #1 on: December 11, 2008, 03:28:29 AM »
You are very close - what is a total pressure? What is definition of mole fraction? How does number of moles depend on the pressure (for a given V, T)?
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Offline plat_num

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Re: Calculating Mole Fractions
« Reply #2 on: December 11, 2008, 07:41:16 PM »
Since pressure and moles are proportional (PV=nRT) wouldn't the mole pressure simply be 155torr/(155torr+62torr)?

Offline Borek

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Re: Calculating Mole Fractions
« Reply #3 on: December 11, 2008, 07:50:59 PM »
No, you don't have pure substances, you have a mixture of them. And you have already calculated their individual pressures.
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Offline plat_num

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Re: Calculating Mole Fractions
« Reply #4 on: December 11, 2008, 08:00:36 PM »
No, you don't have pure substances, you have a mixture of them. And you have already calculated their individual pressures.

Could you then do PV=nrt (drop the V since it's constant in both) so P/RT= n? 

Then once you found the moles of both substances in the vapour simply divide each by the total moles present?     

Offline plat_num

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Re: Calculating Mole Fractions
« Reply #5 on: December 11, 2008, 08:05:15 PM »
Wait, I'm obviously missing something...  You would use the 35.65 torr and the 47.74 torr as the pressures to plug into n=P/RT.  That would give you the moles of each pure compound.  Then take THOSE moles, and divide them by the total moles you'd find in the vapour.  Is that right?  or am I way off base here?

Offline plat_num

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Re: Calculating Mole Fractions
« Reply #6 on: December 11, 2008, 08:51:14 PM »
Sorry for being all over the place, I'm all over the place i'm new to this chemistry buisness :)

Since pressure and moles are proportional I'm thinking you wouldn't NEED to convert anything to moles would you?  All you have to do is add 35.65torr and 47.74torr, and then divide each of your partial pressures by that sum, to get the individual mole fractions of the vapour gas! 

Offline Borek

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Re: Calculating Mole Fractions
« Reply #7 on: December 12, 2008, 03:39:31 AM »
Since pressure and moles are proportional I'm thinking you wouldn't NEED to convert anything to moles would you?  All you have to do is add 35.65torr and 47.74torr, and then divide each of your partial pressures by that sum, to get the individual mole fractions of the vapour gas!

Bingo.
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Offline plat_num

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Re: Calculating Mole Fractions
« Reply #8 on: December 12, 2008, 01:05:21 PM »
s#*$, this chemistry stuff is turning out to be pretty cool after all.

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