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Topic: Solutions m/v: 2.3 L of normal saline solution 0.90% NaCl  (Read 5260 times)

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MAchemi

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Solutions m/v: 2.3 L of normal saline solution 0.90% NaCl
« on: April 30, 2005, 02:22:16 PM »
This is the problem.  Calculate the grams of solute required to make the following solution.  2.3 L of normal saline solution (0.90% NaCl (m/v))

My book, notes, and all wbsites I have found say that m/v is grams over 100 ml.  I tried .9 grams over 100 ml, and multiplied by 2300 ml, I tried .9g/1 L times 2.3 L, and several other variations.  They all come to 2.07, or 207 etc.  I tried these, and i tried changing the number of significant figures, but none are right.  This is webassign homework, and it is due sunday may 2nd at midnight, so please, i need help before then!
« Last Edit: April 30, 2005, 06:22:56 PM by Mitch »

Offline Borek

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Re:Solutions m/v
« Reply #1 on: April 30, 2005, 05:51:00 PM »
Try CASC (see footer). Especially read remarks on %w/v concentration in the program help.

207 are proper digits, the question is - where to put decimal point? You need 0.9g per 100 mL, how many 100 mL is in 2300 mL?
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MAchemi

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Re:Solutions m/v: 2.3 L of normal saline solution 0.90% NaCl
« Reply #2 on: May 01, 2005, 11:09:04 AM »
That's great-I got it right!  20.7!  Thanks-that's a great site!

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