[lildarkangel13]

how does the lewid dot strucutre look for it.... i think it has 2 lone pairs and 2 bonds, but im not sure... right? PLEASE HELP MEEE...im really confused about this problem..thank you

[plat_num]

2 lone pairs + 2 bonds = 8 electrons.  Doesn't [PH2]+ only have 6 valence bonds available for bonding?

[Bioionic]

PH2 does not exist I think, but PH2+ means one electron is lost so there is 6 e-.  So we should have H-:P-H

Two bonds = 4 e- two lone pairs 2 e- = 6e-
Sounds like two bonds two lone pairs.

[plat_num]

Bioionic, if there is only 6 electrons available for bonding and there are 2 bonds (2*2=4) wouldn't that mean that there's only 2 (6-4=2) electrons left over, or ONE lone pair?  Wouldn't 2 lone pairs require and EXTRA two electrons for a total of 8?

[Bioionic]

Your right, 1 pair. Thats what I meant...

[lildarkangel13]

thanksss guyss..this question was in my chem test

i realized that if theres 2 bonds and 2 lone pairs in the P, then it would be [PH2]-

but if theres 2 bonds and 1 lone pair in the P, then it would be [PH2]+

I  was just confused because i wasnt sure whether  P  follows the octet rule in this case, since it only has 6 e- in [PH2]+