Sorry about my english:
need to calculate the pH of 2 solutions mixed together:
120 ml H3PO4 0.15 Normal
40 ml KOH 0.4 Molar
Ka1 = 7.5 x 10^-3
Ka2 = 6.2 x 10^-8
Ka3 = 4.8 x 10^-13
What I did, but apparently is incorrect:
0.15 N ---> 0.05 M ---> 0.006 moles of the acid
0.016 moles of the base - 0.006 = 0.01
and I found the [OH-] and then the [H3O+]. But - my answer is slightly different then the one in the book, and secondly I did not use the Ka's.
So, any suggestions of the steps I should take ?
What reactions are taking place here ?
Thank you in advance.