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Topic: Stoicheometery sodium azide  (Read 2891 times)

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Offline oneeyed5

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Stoicheometery sodium azide
« on: January 13, 2009, 05:34:40 PM »
2NaN3(s)-------> 2Na(s) + 3N2

What volume of gas will be produced if 92.0g of sodium azide at 20 degrees celcius and 748mmHg?

How many molecules of nitrogen are present in this volume?

How many atoms of nitrogen are present in this volume?

Can't seem to fit it in with PV=TRn
What is 748mmHg and how do i convert it to make it fit?
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Offline Borek

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Re: Stoicheometery sodium azide
« Reply #1 on: January 13, 2009, 06:19:13 PM »
mmHg is a unit of pressure, you should be able to google it.
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Offline oneeyed5

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Re: Stoicheometery sodium azide
« Reply #2 on: January 13, 2009, 06:20:54 PM »
100kPa would that make the equation

100kPa/(293k)(8.31)(1.4mol)

I got .029L im still confused for b and c
not even sure if i had equation right
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Offline Borek

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Re: Stoicheometery sodium azide
« Reply #3 on: January 14, 2009, 03:07:16 AM »
You are correct about 1.4 mole. However, your volume is off, which will be obvious once you try to find out the answer units - silently ignoring units of gas constant is not helping. You are close, but you made a mistake when solving for V.

b & c - how many molecules per mole? How many nitrogen atoms per molecule?
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