A chemical engineer sutdying the properties of fuels placed 1.520 g of a hydrocarbon in the bomb of a calorimeter and filled it with O2 gas. The bomb was immersed in 2.550 L of water and the reaction initiated. The water temperature rose from 20.00 C to 23.55 C. If the calorimeter (excluding the water) had a heat capacity of 403 J/K,w hat was the heat of reaction for combustion (qv) per gram of the fuel?
My first step at attacking this problem was to set up -qsample= qcalorimeter
-(1.520g*q) = 403J/K(3.55K)
Actually, I have no idea now that I look back. Any tips on what to set up and what to solve for? Thank you!