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Topic: Bomb Calorimeter Problem!  (Read 4315 times)

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Offline Zoloft

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Bomb Calorimeter Problem!
« on: January 17, 2009, 02:25:24 AM »
A chemical engineer sutdying the properties of fuels placed 1.520 g of a hydrocarbon in the bomb of a calorimeter and filled it with O2 gas. The bomb was immersed in 2.550 L of water and the reaction initiated. The water temperature rose from 20.00 C to 23.55 C. If the calorimeter (excluding the water) had a heat capacity of 403 J/K,w hat was the heat of reaction for combustion (qv) per gram of the fuel?

My first step at attacking this problem was to set up -qsample= qcalorimeter
-(1.520g*q) = 403J/K(3.55K)

Actually, I have no idea now that I look back. Any tips on what to set up and what to solve for? Thank you!

Offline Zoloft

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Re: Bomb Calorimeter Problem!
« Reply #1 on: January 17, 2009, 02:45:01 AM »
Hmmm.

Do I set up qreaction = -(qwater + qcalorimeter) ?

And at the end, divide my given mass which is 1.520 g by the resulting joules, right?

Offline Borek

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Re: Bomb Calorimeter Problem!
« Reply #2 on: January 17, 2009, 04:32:55 AM »
You seem to be on the right track now.
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