April 26, 2024, 12:48:33 AM
Forum Rules: Read This Before Posting


Topic: Chemical Equillibrium  (Read 2543 times)

0 Members and 1 Guest are viewing this topic.

Offline myoplex11

  • Regular Member
  • ***
  • Posts: 9
  • Mole Snacks: +0/-0
Chemical Equillibrium
« on: January 29, 2009, 06:27:18 AM »
A + B -> C + D (reversible reaction)

a 2L container contains 1 mol of C, 1.6 mol of D, 0.8 mol of A snd 0.8 mol of B. Calculate the equillibrium composition of the reaction. Kc =0.065

I think C and D are forming A and B because there is higher concentration of C and D. So equillbrium concentrations will be C = 0.5 -x
D =0.800 -x , A = 0.400 + x, B = 0.400+x and then i can sovle for x by plugging these values into my equillibrum expession and setting it equal to Kc(.0065) I my approach correct? 

Offline Donaldson Tan

  • Editor, New Asia Republic
  • Retired Staff
  • Sr. Member
  • *
  • Posts: 3177
  • Mole Snacks: +261/-13
  • Gender: Male
    • New Asia Republic
Re: Chemical Equillibrium
« Reply #1 on: January 29, 2009, 09:56:14 AM »
Your approach is correct. However, do not be surprised if X is negative in some cases.
"Say you're in a [chemical] plant and there's a snake on the floor. What are you going to do? Call a consultant? Get a meeting together to talk about which color is the snake? Employees should do one thing: walk over there and you step on the friggin� snake." - Jean-Pierre Garnier, CEO of Glaxosmithkline, June 2006

Sponsored Links