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Offline ahawk1

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problem solving
« on: January 31, 2009, 11:10:42 PM »
To the alchemists, gold was the material representation of purity. It is a very soft metal that can be hammered into extremely thin sheets. If a 1.15 g piece of gold is hammered into a sheet whose area is 38.4 ft2, what is the average thickness of the sheet? (The density of gold is 19.32  g/cm3.)

for some reason im just not figuring this out, i think im doing something really stupid. thanks for the help in advance.

Offline macman104

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Re: problem solving
« Reply #1 on: January 31, 2009, 11:16:06 PM »
What is the definition of volume when related to area?  V = Area * ___?

Offline ahawk1

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Re: problem solving
« Reply #2 on: January 31, 2009, 11:24:38 PM »
What is the definition of volume when related to area?  V = Area * ___?
v=area*height?

Offline macman104

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Re: problem solving
« Reply #3 on: January 31, 2009, 11:34:15 PM »
Yup, and you need the height, so make it your x.  Now, what is the equation for density, do you see how you can plug in your volume formula (with your x), and then solve for x?  All the other values are given to you.  Also, make sure your units match before you do this!

Offline ahawk1

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Re: problem solving
« Reply #4 on: January 31, 2009, 11:44:38 PM »
Yup, and you need the height, so make it your x.  Now, what is the equation for density, do you see how you can plug in your volume formula (with your x), and then solve for x?  All the other values are given to you.  Also, make sure your units match before you do this!


ok so when converting the 38.4 ft^2 to cm^2 i would get 35674.8cm^2 or 34560?

Offline macman104

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Re: problem solving
« Reply #5 on: January 31, 2009, 11:46:02 PM »
Show your working.

Offline ahawk1

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Re: problem solving
« Reply #6 on: February 01, 2009, 12:04:25 AM »
Show your working.

19.32g/cm^3=1/1.15g*34560cm^2*hcm

19.32=30052.17391h
h=6.4288e-04cm?

Offline macman104

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Re: problem solving
« Reply #7 on: February 01, 2009, 12:12:48 AM »
Setup is correct, but you had a question about the conversion from ft^2 to cm^2, I was saying post that calculation.

Offline ahawk1

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Re: problem solving
« Reply #8 on: February 01, 2009, 12:22:49 AM »
Setup is correct, but you had a question about the conversion from ft^2 to cm^2, I was saying post that calculation.

38.4ft^2*(900cm^2/1ft^2)

Offline macman104

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Re: problem solving
« Reply #9 on: February 01, 2009, 12:29:59 AM »
You should use 1 ft = 30.48cm not 30cm, it's an exact value (based on 1 inch = 2.54 cm is an exact value as well).

Offline ahawk1

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Re: problem solving
« Reply #10 on: February 01, 2009, 12:32:06 AM »
You should use 1 ft = 30.48cm not 30cm, it's an exact value (based on 1 inch = 2.54 cm is an exact value as well).
hmmm using that i get h=6.228e-4cm and that is still incorrect

Offline macman104

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Re: problem solving
« Reply #11 on: February 01, 2009, 12:42:43 AM »
Sorry, not quite correct.  When you substitute the formula for volume in, you should get:

Density = Mass/Area*Height

You had:

Density = 1/Mass*Area*Height

Rearranging should have given you:

Height = Density*Area/Mass

Offline ahawk1

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Re: problem solving
« Reply #12 on: February 01, 2009, 12:51:29 AM »
Sorry, not quite correct.  When you substitute the formula for volume in, you should get:

Density = Mass/Area*Height

You had:

Density = 1/Mass*Area*Height

Rearranging should have given you:

Height = Density*Area/Mass

thanks for sticking with me. my algebra skills have failed for me once again. i got that problem right now,  thanks very much!

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