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Topic: Figuring out volume using energy transfer  (Read 4165 times)

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Offline fortyforty

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Figuring out volume using energy transfer
« on: February 01, 2009, 02:06:45 PM »
hey guys if you could just help me with this question it would be great...here it is

A cube of gold is heated to a temperature of 94.2 degrees Celsius, and then submerged in 31.3 mL (31.3 g) of H20 (water) at an initial temperature of 28.7 degrees Celsius.  If the final temperature of the water is 45.6 degrees Celsius, calculate the volume of the cube of gold (in mL).  Gold is a metal with a specific heat of 0.130 J/g degrees Celsius and a density of 19.3 g/mL.

I think that it has to do something with figuring out the displacement of water using how much energy was used to heat up the water but i cannot figure out what formula to use.  The only formula that i know i can use in this situation is Q=sm(delta)T.  I have tried numerous combination's but i cant seem to get the answer

If you guys could just help me out it would be great....thanks

Offline Astrokel

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Re: Figuring out volume using energy transfer
« Reply #1 on: February 01, 2009, 02:20:46 PM »
Could you post your work here?
No matters what results are waiting for us, it's nothing but the DESTINY!!!!!!!!!!!!

Offline fortyforty

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Re: Figuring out volume using energy transfer
« Reply #2 on: February 01, 2009, 02:31:53 PM »
s=.130 J/g degrees Celsius
m = 31.3 g
change in T - 16.9 degrees celsius

but i dont understand it at all because .130 is the specific heat of gold and not water so i cant do that.  like i have no idea what numbers to use in the question and where to use them....i am sort of just going out on a limb and plugging in numbers where i think they belong. 

Offline Astrokel

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Re: Figuring out volume using energy transfer
« Reply #3 on: February 01, 2009, 03:15:54 PM »
Quote
like i have no idea what numbers to use in the question and where to use them....i am sort of just going out on a limb and plugging in numbers where i think they belong. 

Ok take it slowly and you are right about using Q = mc :delta: T

By law of conservation of energy,

Qloss = Qgain

Which(gold or water) loss & gain heat?

Are you not given specific heat capacity of water?
No matters what results are waiting for us, it's nothing but the DESTINY!!!!!!!!!!!!

Offline fortyforty

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Re: Figuring out volume using energy transfer
« Reply #4 on: February 01, 2009, 06:42:11 PM »
sorry.....ya thats the exact question im not given anything else at all

Offline ARGOS++

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Re: Figuring out volume using energy transfer
« Reply #5 on: February 01, 2009, 06:54:26 PM »

Dear fortyforty;

But you can search the Internet or Wiki for the spec. heat capacity of water.
Then you have all what is required for Qloss = Qgain.

Good Luck!
                    ARGOS++


Offline fortyforty

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Re: Figuring out volume using energy transfer
« Reply #6 on: February 01, 2009, 08:31:11 PM »
ya guys i got it thanks a lot....your help is greatly appreciated

Offline ARGOS++

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Re: Figuring out volume using energy transfer
« Reply #7 on: February 01, 2009, 08:36:47 PM »

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