w/e i gave up on that problem because it frustrated me and i started the last one....

**26.46 KJ of energy is released from 10.00 grams of steam as it condenses from 125.00*C. What is the final temerature of the condensed water?**

(.5 cal/g *C)(10.00g)(100-125) + (-540 cal/g)(10.00g)+(1.0 cal/g)(10.00g)(F-100*C) = 6323 calories

-125 cal + 5400 cal + 10 cal/g(F-100*C)=6323 calories

(10.00 cal/g)(F^{o} - 100*C) = 1038 calories

10.00 cal/g F^{o}

1038 calories

------------- = **103.8 *C**

10.00 cal/g F^{o}