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Topic: 1st law of thermodynamic  (Read 3428 times)

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Offline o0CY0o

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1st law of thermodynamic
« on: February 15, 2009, 03:53:42 AM »
I'm an undergraduate yr 1 student.
I'm facing some problem in studying physical chemisty.
The part for thermodynamic.
I clearly understand how the things are derived.
Yet, I cannot figure the situation problems.
Can practise help?




I got a question which i found on the web and want to share with you guys.

The value of C(constant pressure) for a sample of a perfect gas was found to vary with temperature according to the expression C=20.17+0.3665T where T is tempreature in Kelvin. Calculate q,q,delta U and delta H for 1 mol of gas raised from 25 degree C to 200 degree C at constant pressure

Offline Yggdrasil

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Re: 1st law of thermodynamic
« Reply #1 on: February 15, 2009, 01:07:38 PM »
Well, since the process occurs at constant pressure, you can immediately say something about q, ΔU and ΔH.  Also, to solve for one of these quantities, because Cp varies with temperature, you'll need to convert one of your formulas into an integral over dT.

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