May 06, 2021, 12:50:49 PM
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### Topic: Graham's law practice  (Read 10285 times)

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#### ARGOS++

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##### Re: Graham's law practice
« Reply #15 on: February 16, 2009, 08:42:31 PM »

Dear reezyfbaby;

No!, - your equation is not balanced anymore!

Itâ€™s simple algebra, so I simply get:
vUK2 / vCO22    =    MWCO2  /  MWUK

Can you now solve the equation for MWUK?

Good Luck!
ARGOS++

#### mr cool

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##### Re: Graham's law practice
« Reply #16 on: February 16, 2009, 08:56:17 PM »
6.00 UK2 / 12 CO22 = 44.0095 g CO2 / mw uk

I have no clue what to do next. We had square roots in the whole problem we did in class.

#### ARGOS++

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##### Re: Graham's law practice
« Reply #17 on: February 16, 2009, 09:06:44 PM »
Dear reezyfbaby;

You inserted values instead of rearranging the law for MWUK!
And you used the wrong values for the speeds.

Please try to rearrange the formula before you insert any value!!

Think: How fast is CO2, and what means twice so fast?

As you are asked for the MW so you have to remove/solve the square roots!!
Good Luck!
ARGOS++