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Topic: Q=M(DELTA)!!!  (Read 2442 times)

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Offline xCensored

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Q=M(DELTA)!!!
« on: February 24, 2009, 05:38:17 PM »
1. How much heat (J) is released when 25.0 g steam at 345 oC cools down to 125 oC?
 
I'm not sure what formula to be using. So far what I know, is that you have to like.. subtract 125 from 345 and then multiply by 25? What formula is that, is that Q=M(DELTA)T? or no?

Offline Borek

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Re: Q=M(DELTA)!!!
« Reply #1 on: February 24, 2009, 05:47:32 PM »
q = c m  :delta: T
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