I am having trouble with a couple of chemistry problems. One I was able to answer half of, and the other I don't even know how to start. Any help would be greatly appreciated!
Use the dilution relationship (Mi x Vi = Mf x Vf) to calculate the volume of 0.500 M NaOH needed to prepare 500 mL of 0.250 M NaOH.
? mL x .500 M NaOH = (500mL x.250M)/.500 = 250 mL
Now here is where I am lost with this problem:
What volume of water would you add to the 0.500 M NaOH volume calculated aove to actually make 500 mL of 0.250 M NaOH?
49.22 mL of a 2.01 M NaOH solution reacts completely with 40.28 mL of HCl solution according to the balanced chemical reaction shown below:
HCl (aq) + NaOH(ap) -> NaCl(aq) + H2O(i)
How many moles of HCl reacted?