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Topic: Empirical Formula. my answer is different from the book. please help  (Read 6597 times)

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Offline MichelleL

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Here is the Questions: Determine the empirical formula of each of the following compounds. The percentage compositon by mass is givin.
52.9% aluminum 47.1% oxygen
Work done...
m = 52.9g Al m=47.1g O
nAl = 52.9g divided by 26.98g/mol = 1.96 mol
nO = 47.1g divided by 16g/mol =2.94 mol
Al ratio = 2.94 divided by 1.96 = 1.5
O ratio = 1.96 divided by 1.96 = 1
But because it is not a whole number...
Al 1.5 X 2 =3
o  1 x 2 = 2   ... (what you do to one you do to the other 2X?)
Therefore Al3O2
But the answer in the back of the book is Al2O3

I'm confused on where i am going wrong.

I do have a few other questions in past sections but will make other post for. I am taking school from the independed learning center and it takes 5 bus days to get someone to call back. I have time today so I found this site. Looks really good and I am looking forward to some help.

Offline ARGOS++

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Re: Empirical Formula. my answer is different from the book. please help
« Reply #1 on: March 01, 2009, 05:02:36 PM »

Dear MichelleL;

Please tell why you divide each by 1.96?

As both values are close to the next Integer, so you can only round to it.

Good Luck!
                    ARGOS++

Offline MichelleL

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Re: Empirical Formula. my answer is different from the book. please help
« Reply #2 on: March 01, 2009, 05:08:28 PM »
Thank you for the quick response
well, I only have one example in my book to follow and in step three it says divide both moles by the smallest number of moles...

um... if i was to round up... then the answer would still be Al3o2 ... I don't understand why the answer in the back of my book says Al2O3 . I feel like I'm just not understanding one part of this. 

Offline MichelleL

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Re: Empirical Formula. my answer is different from the book. please help
« Reply #3 on: March 01, 2009, 05:14:45 PM »
oh yes and my book says for me to choose a total mass and it is easiest to consider 100g of a subsance since the percentages are out of 100%.

Offline ARGOS++

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Re: Empirical Formula. my answer is different from the book. please help
« Reply #4 on: March 01, 2009, 05:15:48 PM »

Dear MichelleL;

The atomic ratio you have already given with the percentage.
So you tell that your formula must be build with 1.96 moles of Al and 2.94 moles of O,
   -  or in short:  Al1.96O2.94.
The last Step is left to you.

Good Luck!
                    ARGOS++

Offline MichelleL

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Re: Empirical Formula. my answer is different from the book. please help
« Reply #5 on: March 01, 2009, 05:23:08 PM »
oh wow. lol. ok I'm laughing now. thank you. I understand now. :)

Offline ARGOS++

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Re: Empirical Formula. my answer is different from the book. please help
« Reply #6 on: March 01, 2009, 05:25:38 PM »

Dear MichelleL;

Do you see now where you did the mistake?
By your division by 1.96 you intermixed both Al & O ratios!!

Good Luck!
                    ARGOS++

Offline MichelleL

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Re: Empirical Formula. my answer is different from the book. please help
« Reply #7 on: March 01, 2009, 05:28:55 PM »
yes  :). I was staring right at the answer and didn't even know it. lol.

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